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What is Herbert's highest singles ranking?

  • World No. 36

  • World No. 25

  • World No. 50

  • World No. 45

Answer

Herbert's highest singles ranking is World No. 36, achieved on November 18, 2019. This ranking reflects his consistent performances on the ATP Tour, where he has reached the semifinals or better at several tournaments, including the 2019 Miami Open and the 2020 ATP Cup. Herbert's success in singles is a testament to his all-court game, which combines powerful groundstrokes with deft touch and volleying skills.
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